Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- 19*x+2*y=17
- 8*x-9*y=-1
- 13*x-1*y=-20
- 9*x+8*y=-4
- Equation:
-
Equation cos(x)-1=0
-
Equation x+5=7
-
Equation 16*x^3+8*x^2+x=0
-
Equation 3/5*y=29/10-1/5
- Integral of d{x}:
- -9
- Limit of the function:
-
-9
-
Identical expressions
- - three *x- nineteen *y=- nine
- minus 3 multiply by x minus 19 multiply by y equally minus 9
- minus three multiply by x minus nineteen multiply by y equally minus nine
- -3x-19y=-9
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Similar expressions
- -3*x-19*y=+9
- 3*x-19*y=-9
- -3*x+19*y=-9
Express x in terms of y where -3*x-19*y=-9
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 3 x = 19 y - 9$$
Divide both parts of the equation by -3
We get the answer: x = 3 - 19*y/3
-3*x-19*y = -9
Looking for similar summands in the left part:
-19*y - 3*x = -9
Move the summands with the other variables
from left part to right part, we given:
$$- 3 x = 19 y - 9$$
Divide both parts of the equation by -3
x = -9 + 19*y / (-3)
We get the answer: x = 3 - 19*y/3
Rapid solution
[src]
19*re(y) 19*I*im(y)
x1 = 3 - -------- - ----------
3 3
$$x_{1} = - \frac{19 \operatorname{re}{\left(y\right)}}{3} - \frac{19 i \operatorname{im}{\left(y\right)}}{3} + 3$$
x1 = -19*re(y)/3 - 19*i*im(y)/3 + 3