Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation x^3=3
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Equation 5-x^2=0
- Equation (-5*x+3)*(-x+8)=0
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Equation 5x^2+9x+4=0
- Express {x} in terms of y where:
- -6*x+11*y=-5
- -3*x-19*y=-9
- 16*x+14*y=-14
- 3*x-14*y=-2
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Identical expressions
- ((eight *x- five)/ three)-((four *x+ three)/ four)+((two - nine *x)/ two)= zero
- ((8 multiply by x minus 5) divide by 3) minus ((4 multiply by x plus 3) divide by 4) plus ((2 minus 9 multiply by x) divide by 2) equally 0
- ((eight multiply by x minus five) divide by three) minus ((four multiply by x plus three) divide by four) plus ((two minus nine multiply by x) divide by two) equally zero
- ((8x-5)/3)-((4x+3)/4)+((2-9x)/2)=0
- 8x-5/3-4x+3/4+2-9x/2=0
- ((8*x-5)/3)-((4*x+3)/4)+((2-9*x)/2)=O
- ((8*x-5) divide by 3)-((4*x+3) divide by 4)+((2-9*x) divide by 2)=0
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Similar expressions
- ((8*x-5)/3)-((4*x-3)/4)+((2-9*x)/2)=0
- ((8*x-5)/3)+((4*x+3)/4)+((2-9*x)/2)=0
- ((8*x-5)/3)-((4*x+3)/4)-((2-9*x)/2)=0
- ((8*x+5)/3)-((4*x+3)/4)+((2-9*x)/2)=0
- ((8*x-5)/3)-((4*x+3)/4)+((2+9*x)/2)=0
((8*x-5)/3)-((4*x+3)/4)+((2-9*x)/2)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
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[src]
8*x - 5 4*x + 3 2 - 9*x ------- - ------- + ------- = 0 3 4 2
$$\frac{2 - 9 x}{2} + \left(- \frac{4 x + 3}{4} + \frac{8 x - 5}{3}\right) = 0$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- \frac{17 x}{6} = \frac{17}{12}$$
Divide both parts of the equation by -17/6
We get the answer: x = -1/2
((8*x-5)/3)-((4*x+3)/4)+((2-9*x)/2) = 0
Expand brackets in the left part
8*x/3-5/3)-4*x/4-3/4)+2/2-9*x/2) = 0
Looking for similar summands in the left part:
-17/12 - 17*x/6 = 0
Move free summands (without x)
from left part to right part, we given:
$$- \frac{17 x}{6} = \frac{17}{12}$$
Divide both parts of the equation by -17/6
x = 17/12 / (-17/6)
We get the answer: x = -1/2
Sum and product of roots
[src]
sum
-1/2
$$- \frac{1}{2}$$
=
-1/2
$$- \frac{1}{2}$$
product
-1/2
$$- \frac{1}{2}$$
=
-1/2
$$- \frac{1}{2}$$
-1/2