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(x-3)*(x+2)=0

(x-3)*(x+2)=0 equation

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Numerical solution:

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The solution

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(x - 3)*(x + 2) = 0
$$\left(x - 3\right) \left(x + 2\right) = 0$$
Detail solution
Expand the expression in the equation
$$\left(x - 3\right) \left(x + 2\right) = 0$$
We get the quadratic equation
$$x^{2} - x - 6 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -1$$
$$c = -6$$
, then
D = b^2 - 4 * a * c = 

(-1)^2 - 4 * (1) * (-6) = 25

Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)

x2 = (-b - sqrt(D)) / (2*a)

or
$$x_{1} = 3$$
$$x_{2} = -2$$
The graph
Rapid solution [src]
x1 = -2
$$x_{1} = -2$$
x2 = 3
$$x_{2} = 3$$
x2 = 3
Sum and product of roots [src]
sum
-2 + 3
$$-2 + 3$$
=
1
$$1$$
product
-2*3
$$- 6$$
=
-6
$$-6$$
-6
Numerical answer [src]
x1 = -2.0
x2 = 3.0
x2 = 3.0
The graph
(x-3)*(x+2)=0 equation