Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (x+2)/9=(x-3)/2
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Equation (x-2)^4+3*(x-2)^2-10=0
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Equation 3*x^2-18=0
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Equation (x-3)*(x+2)=0
- Express {x} in terms of y where:
- 2*x+3*y=14
- 18*x-8*y=-2
- 16*x-7*y=-5
- 10*x-16*y=-6
- Graphing y =:
- (x-3)*(x+2)
-
Identical expressions
- (x- three)*(x+ two)= zero
- (x minus 3) multiply by (x plus 2) equally 0
- (x minus three) multiply by (x plus two) equally zero
- (x-3)(x+2)=0
- x-3x+2=0
- (x-3)*(x+2)=O
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Similar expressions
- (2x-1)^2-4(x-3)(x+2)=0
- (x+3)*(x+2)=0
- -2*x-3*x+27=0
- arctg(x)-3x+2=0
- (x-3)*(x-2)=0
- arctgh(x)-x-3x+2=0
(x-3)*(x+2)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Expand the expression in the equation
$$\left(x - 3\right) \left(x + 2\right) = 0$$
We get the quadratic equation
$$x^{2} - x - 6 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -1$$
$$c = -6$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 3$$
$$x_{2} = -2$$
$$\left(x - 3\right) \left(x + 2\right) = 0$$
We get the quadratic equation
$$x^{2} - x - 6 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -1$$
$$c = -6$$
, then
D = b^2 - 4 * a * c =
(-1)^2 - 4 * (1) * (-6) = 25
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 3$$
$$x_{2} = -2$$
The graph