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(2x-1)^2-4(x-3)(x+2)=0 equation

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Numerical solution:

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The solution

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         2                        
(2*x - 1)  - 4*(x - 3)*(x + 2) = 0
$$- 4 \left(x - 3\right) \left(x + 2\right) + \left(2 x - 1\right)^{2} = 0$$
Sum and product of roots [src]
sum
0
$$0$$
=
0
$$0$$
product
1
$$1$$
=
1
$$1$$
1