Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 25*x^3-10*x^2+x=0
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Equation 2x^2-x-1=x^2-5x-(-1-x^2)
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Equation 2^x=5
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Equation (x-10)^2=(x+4)^2
- Express {x} in terms of y where:
- 15*x+12*y=-19
- -19*x-20*y=-4
- -18*x+12*y=-8
- -14*x+4*y=-16
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Identical expressions
- (x- three)*(x- two)= zero
- (x minus 3) multiply by (x minus 2) equally 0
- (x minus three) multiply by (x minus two) equally zero
- (x-3)(x-2)=0
- x-3x-2=0
- (x-3)*(x-2)=O
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Similar expressions
- x-3x-2/53-2x-5/3
- (5x-3)(x-2)=0
- (x-3)*(x+2)=0
- (x+3)*(x-2)=0
(x-3)*(x-2)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Expand the expression in the equation
$$\left(x - 3\right) \left(x - 2\right) = 0$$
We get the quadratic equation
$$x^{2} - 5 x + 6 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -5$$
$$c = 6$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 3$$
$$x_{2} = 2$$
$$\left(x - 3\right) \left(x - 2\right) = 0$$
We get the quadratic equation
$$x^{2} - 5 x + 6 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -5$$
$$c = 6$$
, then
D = b^2 - 4 * a * c =
(-5)^2 - 4 * (1) * (6) = 1
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 3$$
$$x_{2} = 2$$
The graph