Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation x^2-2x=0
-
Equation x^2-3x-10=0
-
Equation (x-119)/(x+7)=-5
-
Equation x/4+13=x+1
- Express {x} in terms of y where:
- 15*x-5*y=-5
- 18*x+20*y=-2
- 15*x+7*y=2
- 12*x-20*y=10
-
Identical expressions
- (x- three)*(x- two)= zero
- (x minus 3) multiply by (x minus 2) equally 0
- (x minus three) multiply by (x minus two) equally zero
- (x-3)(x-2)=0
- x-3x-2=0
- (x-3)*(x-2)=O
-
Similar expressions
- x-3x-2/53-2x-5/3
- (5x-3)(x-2)=0
- (x-3)*(x+2)=0
- (x+3)*(x-2)=0
(x-3)*(x-2)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Expand the expression in the equation
$$\left(x - 3\right) \left(x - 2\right) = 0$$
We get the quadratic equation
$$x^{2} - 5 x + 6 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -5$$
$$c = 6$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 3$$
$$x_{2} = 2$$
$$\left(x - 3\right) \left(x - 2\right) = 0$$
We get the quadratic equation
$$x^{2} - 5 x + 6 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -5$$
$$c = 6$$
, then
D = b^2 - 4 * a * c =
(-5)^2 - 4 * (1) * (6) = 1
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 3$$
$$x_{2} = 2$$
The graph