Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation (11x+14)-(5x-8)=25
- Equation x^2-10*x-24=0
- Equation x-y=7
-
Equation 2^x=32
- Express {x} in terms of y where:
- 10*x-18*y=3
- 13*x-12*y=19
- -6*x+12*y=11
- 3*x-7*y=13
- Derivative of:
-
2^x
- Integral of d{x}:
-
2^x
- Graphing y =:
- 2^x
- Expression:
- 32
- Canonical form:
- 32
- 32
-
Identical expressions
- two ^x= thirty-two
- 2 to the power of x equally 32
- two to the power of x equally thirty minus two
- 2x=32
-
Similar expressions
- log3^2(x)-log3(x)^3=-2
- 2^x=16^2
- (3/2)^x=16/81
- 2^x+5^y=320
2^x=32 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$2^{x} = 32$$
or
$$2^{x} - 32 = 0$$
or
$$2^{x} = 32$$
or
$$2^{x} = 32$$
- this is the simplest exponential equation
Do replacement
$$v = 2^{x}$$
we get
$$v - 32 = 0$$
or
$$v - 32 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 32$$
We get the answer: v = 32
do backward replacement
$$2^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(2 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(32 \right)}}{\log{\left(2 \right)}} = 5$$
$$2^{x} = 32$$
or
$$2^{x} - 32 = 0$$
or
$$2^{x} = 32$$
or
$$2^{x} = 32$$
- this is the simplest exponential equation
Do replacement
$$v = 2^{x}$$
we get
$$v - 32 = 0$$
or
$$v - 32 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 32$$
We get the answer: v = 32
do backward replacement
$$2^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(2 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(32 \right)}}{\log{\left(2 \right)}} = 5$$
The graph