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Solving integrals/ 2^x

Integral of 2^x dx

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$$\int\limits_{0}^{1} 2^{x}\, dx$$

Integral(2^x, (x, 0, 1))

Detail solution

The integral of an exponential function is itself divided by the natural logarithm of the base.

$\int 2^{x}\, dx = \frac{2^{x}}{\log{\left(2 \right)}}$
Add the constant of integration:

$\frac{2^{x}}{\log{\left(2 \right)}}+ \mathrm{constant}$

The answer is:

$\frac{2^{x}}{\log{\left(2 \right)}}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                  
 |                x  
 |  x            2   
 | 2  dx = C + ------
 |             log(2)
/

$$\int 2^{x}\, dx = \frac{2^{x}}{\log{\left(2 \right)}} + C$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

  1   
------
log(2)

$$\frac{1}{\log{\left(2 \right)}}$$

  1   
------
log(2)

$$\frac{1}{\log{\left(2 \right)}}$$

1/log(2)

Numerical answer [src]

1.44269504088896

1.44269504088896

The graph

Use the examples entering the upper and lower limits of integration.