2^x=7 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$2^{x} = 7$$
or
$$2^{x} - 7 = 0$$
or
$$2^{x} = 7$$
or
$$2^{x} = 7$$
- this is the simplest exponential equation
Do replacement
$$v = 2^{x}$$
we get
$$v - 7 = 0$$
or
$$v - 7 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 7$$
We get the answer: v = 7
do backward replacement
$$2^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(2 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(7 \right)}}{\log{\left(2 \right)}} = \frac{\log{\left(7 \right)}}{\log{\left(2 \right)}}$$
Sum and product of roots
[src]
$$\frac{\log{\left(7 \right)}}{\log{\left(2 \right)}}$$
$$\frac{\log{\left(7 \right)}}{\log{\left(2 \right)}}$$
$$\frac{\log{\left(7 \right)}}{\log{\left(2 \right)}}$$
$$\frac{\log{\left(7 \right)}}{\log{\left(2 \right)}}$$
log(7)
x1 = ------
log(2)
$$x_{1} = \frac{\log{\left(7 \right)}}{\log{\left(2 \right)}}$$