Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation cos(x)=5
-
Equation x+970=69*32
-
Equation x^3+x^2=0
-
Equation 6*x^2+x-1=0
- Express {x} in terms of y where:
- -17*x+2*y=-4
- 15*x-5*y=-5
- 6*x+7*y=-10
- -19*x-6*y=2
- Derivative of:
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2^x
- Integral of d{x}:
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2^x
- Graphing y =:
- 2^x
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Identical expressions
- two ^x= one
- 2 to the power of x equally 1
- two to the power of x equally one
- 2x=1
-
Similar expressions
- 2^x=16^2
- 8/4^x-6*2^x+1=0
- 2^x+5^y=320
2^x=1 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation:
$$2^{x} = 1$$
or
$$2^{x} - 1 = 0$$
or
$$2^{x} = 1$$
or
$$2^{x} = 1$$
- this is the simplest exponential equation
Do replacement
$$v = 2^{x}$$
we get
$$v - 1 = 0$$
or
$$v - 1 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 1$$
We get the answer: v = 1
do backward replacement
$$2^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(2 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(1 \right)}}{\log{\left(2 \right)}} = 0$$
$$2^{x} = 1$$
or
$$2^{x} - 1 = 0$$
or
$$2^{x} = 1$$
or
$$2^{x} = 1$$
- this is the simplest exponential equation
Do replacement
$$v = 2^{x}$$
we get
$$v - 1 = 0$$
or
$$v - 1 = 0$$
Move free summands (without v)
from left part to right part, we given:
$$v = 1$$
We get the answer: v = 1
do backward replacement
$$2^{x} = v$$
or
$$x = \frac{\log{\left(v \right)}}{\log{\left(2 \right)}}$$
The final answer
$$x_{1} = \frac{\log{\left(1 \right)}}{\log{\left(2 \right)}} = 0$$
The graph