cos(x)=5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
cos(x)=5- this is the simplest trigonometric equation
As right part of the equation
modulo =
True
but cos
can no be more than 1 or less than -1
so the solution of the equation d'not exist.
The graph
Sum and product of roots
[src]
0 + 2*pi - I*im(acos(5)) + I*im(acos(5)) + re(acos(5))
(0+(2π−iim(acos(5))))+(re(acos(5))+iim(acos(5)))
re(acos(5))+2π
1*(2*pi - I*im(acos(5)))*(I*im(acos(5)) + re(acos(5)))
1⋅(2π−iim(acos(5)))(re(acos(5))+iim(acos(5)))
(2*pi - I*im(acos(5)))*(I*im(acos(5)) + re(acos(5)))
(2π−iim(acos(5)))(re(acos(5))+iim(acos(5)))
(2*pi - i*im(acos(5)))*(i*im(acos(5)) + re(acos(5)))
x1 = 2*pi - I*im(acos(5))
x1=2π−iim(acos(5))
x2 = I*im(acos(5)) + re(acos(5))
x2=re(acos(5))+iim(acos(5))
x1 = 6.28318530717959 - 2.29243166956118*i