Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 3*x=12
- Equation x^2+p*x+q=0
-
Equation 4,3x-3,5=2,5x+1,9
-
Equation sin(x)=5/2
- Express {x} in terms of y where:
- -12*x+10*y=2
- -11*x-15*y=-7
- -6*x-6*y=-20
- -9*x-10*y=-20
- Canonical form:
- 120
- Limit of the function:
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120
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Identical expressions
- twelve *x+y= one hundred and twenty
- 12 multiply by x plus y equally 120
- twelve multiply by x plus y equally one hundred and twenty
- 12x+y=120
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Similar expressions
- 12(x+y)=624
- 12*x-y=120
- 10x+12x+y-12y=0
12*x+y=120 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$12 x = 120 - y$$
Divide both parts of the equation by 12
We get the answer: x = 10 - y/12
12*x+y = 120
Looking for similar summands in the left part:
y + 12*x = 120
Move the summands with the other variables
from left part to right part, we given:
$$12 x = 120 - y$$
Divide both parts of the equation by 12
x = 120 - y / (12)
We get the answer: x = 10 - y/12
The graph
Rapid solution
[src]
re(y) I*im(y)
x1 = 10 - ----- - -------
12 12
$$x_{1} = - \frac{\operatorname{re}{\left(y\right)}}{12} - \frac{i \operatorname{im}{\left(y\right)}}{12} + 10$$
x1 = -re(y)/12 - i*im(y)/12 + 10
Sum and product of roots
[src]
sum
re(y) I*im(y)
10 - ----- - -------
12 12
$$- \frac{\operatorname{re}{\left(y\right)}}{12} - \frac{i \operatorname{im}{\left(y\right)}}{12} + 10$$
=
re(y) I*im(y)
10 - ----- - -------
12 12
$$- \frac{\operatorname{re}{\left(y\right)}}{12} - \frac{i \operatorname{im}{\left(y\right)}}{12} + 10$$
product
re(y) I*im(y)
10 - ----- - -------
12 12
$$- \frac{\operatorname{re}{\left(y\right)}}{12} - \frac{i \operatorname{im}{\left(y\right)}}{12} + 10$$
=
re(y) I*im(y)
10 - ----- - -------
12 12
$$- \frac{\operatorname{re}{\left(y\right)}}{12} - \frac{i \operatorname{im}{\left(y\right)}}{12} + 10$$
10 - re(y)/12 - i*im(y)/12