Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation 4,3x-3,5=2,5x+1,9
-
Equation x^6=-64
-
Equation sin(x)=5/2
-
Equation (x+4)(x+2)-(x-0,5)(x+2)=0
- Express {x} in terms of y where:
- -8*x+5*y=-17
- -18*x-17*y=-5
- -13*x+5*y=15
- 13*x-7*y=8
-
Identical expressions
- four , three x-3, five = two ,5x+ one , nine
- 4,3x minus 3,5 equally 2,5x plus 1,9
- four , three x minus 3, five equally two ,5x plus one , nine
-
Similar expressions
- 4,3x-3,5=2,5x-1,9
- 4,3x+3,5=2,5x+1,9
4,3x-3,5=2,5x+1,9 equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
43*x 7 5*x 19 ---- - - = --- + -- 10 2 2 10
$$\frac{43 x}{10} - \frac{7}{2} = \frac{5 x}{2} + \frac{19}{10}$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Move free summands (without x)
from left part to right part, we given:
$$\frac{43 x}{10} = \frac{5 x}{2} + \frac{27}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{9 x}{5} = \frac{27}{5}$$
Divide both parts of the equation by 9/5
We get the answer: x = 3
(43/10)*x-(7/2) = (5/2)*x+(19/10)
Expand brackets in the left part
43/10x-7/2 = (5/2)*x+(19/10)
Expand brackets in the right part
43/10x-7/2 = 5/2x+19/10
Move free summands (without x)
from left part to right part, we given:
$$\frac{43 x}{10} = \frac{5 x}{2} + \frac{27}{5}$$
Move the summands with the unknown x
from the right part to the left part:
$$\frac{9 x}{5} = \frac{27}{5}$$
Divide both parts of the equation by 9/5
x = 27/5 / (9/5)
We get the answer: x = 3
The graph