Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation (-x-4)*(3*x+3)=0
- Equation x^2-144=0
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Equation 25*x^3-10*x^2+x=0
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Equation 12-4(x-3)=39-9x
- Express {x} in terms of y where:
- -1*x+4*y=-10
- 9*x+14*y=-10
- 5*x+19*y=-3
- 15*x+10*y=-4
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Identical expressions
- twelve - four (x- three)= thirty-nine -9x
- 12 minus 4(x minus 3) equally 39 minus 9x
- twelve minus four (x minus three) equally thirty minus nine minus 9x
- 12-4x-3=39-9x
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Similar expressions
- 12-4(x+3)=39-9x
- 12-4(x-3)=39+9x
- 12+4(x-3)=39-9x
- (2x-1)^2-4(x-3)(x+2)=0
12-4(x-3)=39-9x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
Move the summands with the unknown x
from the right part to the left part:
Divide both parts of the equation by 5
We get the answer: x = 3
12-4*(x-3) = 39-9*x
Expand brackets in the left part
12-4*x+4*3 = 39-9*x
Looking for similar summands in the left part:
24 - 4*x = 39-9*x
Move free summands (without x)
from left part to right part, we given:
Move the summands with the unknown x
from the right part to the left part:
Divide both parts of the equation by 5
x = 15 / (5)
We get the answer: x = 3
The graph