Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation x^4=(3*x-4)^2
-
Equation 4-6*(x+2)=3-5*x
-
Equation 1/(x-3)^2-3/(x-3)-4=0
-
Equation 1+sin(x)=0
- Express {x} in terms of y where:
- -11*x+15*y=7
- 6*x+17*y=3
- -17*x+1*y=-11
- 1*x+4*y=20
-
Identical expressions
- twelve - four (x- three)= thirty-nine +9x
- 12 minus 4(x minus 3) equally 39 plus 9x
- twelve minus four (x minus three) equally thirty minus nine plus 9x
- 12-4x-3=39+9x
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Similar expressions
- 12-4(x-3)=39-9x
- 12-4(x+3)=39+9x
- 12+4(x-3)=39+9x
- (2x-1)^2-4(x-3)(x+2)=0
12-4(x-3)=39+9x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 4 x = 9 x + 15$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-13\right) x = 15$$
Divide both parts of the equation by -13
We get the answer: x = -15/13
12-4*(x-3) = 39+9*x
Expand brackets in the left part
12-4*x+4*3 = 39+9*x
Looking for similar summands in the left part:
24 - 4*x = 39+9*x
Move free summands (without x)
from left part to right part, we given:
$$- 4 x = 9 x + 15$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-13\right) x = 15$$
Divide both parts of the equation by -13
x = 15 / (-13)
We get the answer: x = -15/13
Sum and product of roots
[src]
sum
-15 ---- 13
$$- \frac{15}{13}$$
=
-15 ---- 13
$$- \frac{15}{13}$$
product
-15 ---- 13
$$- \frac{15}{13}$$
=
-15 ---- 13
$$- \frac{15}{13}$$
-15/13