Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation 5^x=8^x
-
Equation -27x+220=-5x
-
Equation x+12=5
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Equation 3/(x-5)+8/x=2
- Express {x} in terms of y where:
- 12*x+1*y=15
- -16*x-10*y=4
- -4*x-20*y=10
- 19*x+6*y=8
- Derivative of:
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sqrt(x+4)
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sqrt3x
- Integral of d{x}:
-
sqrt(x+4)
- sqrt3x
- Graphing y =:
- sqrt(x+4)
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Identical expressions
- sqrt(x+ four)=sqrt3x
- square root of (x plus 4) equally square root of 3x
- square root of (x plus four) equally square root of 3x
- √(x+4)=√3x
- sqrtx+4=sqrt3x
-
Similar expressions
- sin(2*x)=sqrt(3)*(x+3*pi/2)
- sqrt(3x-11)-sqrt(3y-35)=4
- 4sqtr(x)-(a+5)2sqrt(x)+4a+4=0
- sqrt(x-4)=sqrt3x
- sqrt(3x+22/16)=10
- 0,85*sqrt((3x+50,6)/(3x-101,2))=0,99
sqrt(x+4)=sqrt3x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$\sqrt{x + 4} = \sqrt{3 x}$$
We raise the equation sides to 2-th degree
$$x + 4 = 3 x$$
Move free summands (without x)
from left part to right part, we given:
$$x = 3 x - 4$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-2\right) x = -4$$
Divide both parts of the equation by -2
We get the answer: x = 2
check:
$$x_{1} = 2$$
$$- \sqrt{3} \sqrt{x_{1}} + \sqrt{x_{1} + 4} = 0$$
=
$$- \sqrt{2 \cdot 3} + \sqrt{2 + 4} = 0$$
=
- the identity
The final answer:
$$x_{1} = 2$$
$$\sqrt{x + 4} = \sqrt{3 x}$$
We raise the equation sides to 2-th degree
$$x + 4 = 3 x$$
Move free summands (without x)
from left part to right part, we given:
$$x = 3 x - 4$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-2\right) x = -4$$
Divide both parts of the equation by -2
x = -4 / (-2)
We get the answer: x = 2
check:
$$x_{1} = 2$$
$$- \sqrt{3} \sqrt{x_{1}} + \sqrt{x_{1} + 4} = 0$$
=
$$- \sqrt{2 \cdot 3} + \sqrt{2 + 4} = 0$$
=
0 = 0
- the identity
The final answer:
$$x_{1} = 2$$