Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 5^x=8^x
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Equation -27x+220=-5x
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Equation x+12=5
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Equation 3/(x-5)+8/x=2
- Express {x} in terms of y where:
- 12*x+1*y=15
- -16*x-10*y=4
- -15*x-13*y=-20
- -4*x-20*y=10
- Sum of series:
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10
- Derivative of:
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10
- Integral of d{x}:
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10
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Identical expressions
- sqrt(3x+ twenty-two / sixteen)= ten
- square root of (3x plus 22 divide by 16) equally 10
- square root of (3x plus twenty minus two divide by sixteen) equally ten
- √(3x+22/16)=10
- sqrt3x+22/16=10
- sqrt(3x+22 divide by 16)=10
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Similar expressions
- sqrt(3x-22/16)=10
sqrt(3x+22/16)=10 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
$$\sqrt{3 x + \frac{11}{8}} = 10$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{3 x + \frac{11}{8}}\right)^{2} = 10^{2}$$
or
$$3 x + \frac{11}{8} = 100$$
Move free summands (without x)
from left part to right part, we given:
$$3 x = \frac{789}{8}$$
Divide both parts of the equation by 3
We get the answer: x = 263/8
The final answer:
$$x_{1} = \frac{263}{8}$$
$$\sqrt{3 x + \frac{11}{8}} = 10$$
Because equation degree is equal to = 1/2 - does not contain even numbers in the numerator, then
the equation has single real root.
We raise the equation sides to 2-th degree:
We get:
$$\left(\sqrt{3 x + \frac{11}{8}}\right)^{2} = 10^{2}$$
or
$$3 x + \frac{11}{8} = 100$$
Move free summands (without x)
from left part to right part, we given:
$$3 x = \frac{789}{8}$$
Divide both parts of the equation by 3
x = 789/8 / (3)
We get the answer: x = 263/8
The final answer:
$$x_{1} = \frac{263}{8}$$
Sum and product of roots
[src]
sum
263/8
$$\frac{263}{8}$$
=
263/8
$$\frac{263}{8}$$
product
263/8
$$\frac{263}{8}$$
=
263/8
$$\frac{263}{8}$$
263/8