Given the equation: x−53+x8=2 Multiply the equation sides by the denominators: x and -5 + x we get: x(x−53+x8)=2x x−511x−40=2x x−511x−40(x−5)=2x(x−5) 11x−40=2x2−10x Move right part of the equation to left part with negative sign.
The equation is transformed from 11x−40=2x2−10x to −2x2+21x−40=0 This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved using the discriminant. The roots of the quadratic equation: x1=2aD−b x2=2a−D−b where D = b^2 - 4*a*c - it is the discriminant. Because a=−2 b=21 c=−40 , then