Given the equation sin(4x−8π)=0 - this is the simplest trigonometric equation
with the change of sign in 0
We get: sin(4x−8π)=0
Divide both parts of the equation by -1
The equation is transformed to cos(4x+83π)=0 This equation is transformed to 4x+83π=πn+acos(0) 4x+83π=πn−π+acos(0) Or 4x+83π=πn+2π 4x+83π=πn−2π , where n - is a integer Move 83π to right part of the equation with the opposite sign, in total: 4x=πn+8π 4x=πn−87π Divide both parts of the equation by 41 we get the answer: x1=4πn+2π x2=4πn−27π