Mister Exam
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How to use it?
- Equation:
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Equation (x+2)^2=(1-x)^2
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Equation 2*cos(x)+1=0
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Equation (-5*x-3)*(2*x-1)=0
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Equation x^2-8x+15=0
- Express {x} in terms of y where:
- 7*x+13*y=-13
- 7*x+19*y=12
- 1*x+20*y=-17
- 14*x-16*y=-3
- Limit of the function:
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5-6*x
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Identical expressions
- nine - seven *(x+ three)= five - six *x
- 9 minus 7 multiply by (x plus 3) equally 5 minus 6 multiply by x
- nine minus seven multiply by (x plus three) equally five minus six multiply by x
- 9-7(x+3)=5-6x
- 9-7x+3=5-6x
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Similar expressions
- x*4=25-6x
- 9-7*(x+3)=5+6*x
- 9-7*(x-3)=5-6*x
- 9+7*(x+3)=5-6*x
- /1,5-6x/=2,5
9-7*(x+3)=5-6*x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 7 x = - 6 x + 17$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 17$$
Divide both parts of the equation by -1
We get the answer: x = -17
9-7*(x+3) = 5-6*x
Expand brackets in the left part
9-7*x-7*3 = 5-6*x
Looking for similar summands in the left part:
-12 - 7*x = 5-6*x
Move free summands (without x)
from left part to right part, we given:
$$- 7 x = - 6 x + 17$$
Move the summands with the unknown x
from the right part to the left part:
$$- x = 17$$
Divide both parts of the equation by -1
x = 17 / (-1)
We get the answer: x = -17
Sum and product of roots
[src]
sum
0 - 17
$$-17 + 0$$
=
-17
$$-17$$
product
1*-17
$$1 \left(-17\right)$$
=
-17
$$-17$$
-17
The graph