Mister Exam
Other calculators
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How to use it?
- Equation:
- Equation (x^2-81)^2+(x^2+5x-36)^2=0
-
Equation x^2+9x+20=0
-
Equation (x+340)-152=214
- Equation x^2-4i=0
- Express {x} in terms of y where:
- 4*x-16*y=6
- 10*x-1*y=10
- sqrt(x^2+y^2+4x-6y-12)+(x^2+10x-27)=8-|y-9|+|y-3|
- 15*x-17*y=19
- Limit of the function:
-
|x|
- Derivative of:
-
|x|
- Integral of d{x}:
- |x|
-
Identical expressions
- |x|= one
- module of x| equally 1
- module of x| equally one
|x|=1 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$x - 1 = 0$$
after simplifying we get
$$x - 1 = 0$$
the solution in this interval:
$$x_{1} = 1$$
2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$- x - 1 = 0$$
after simplifying we get
$$- x - 1 = 0$$
the solution in this interval:
$$x_{2} = -1$$
The final answer:
$$x_{1} = 1$$
$$x_{2} = -1$$
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$x - 1 = 0$$
after simplifying we get
$$x - 1 = 0$$
the solution in this interval:
$$x_{1} = 1$$
2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$- x - 1 = 0$$
after simplifying we get
$$- x - 1 = 0$$
the solution in this interval:
$$x_{2} = -1$$
The final answer:
$$x_{1} = 1$$
$$x_{2} = -1$$
The graph