Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation -x/12+x=55/12
- Equation x-y=1
-
Equation 3(x+3)=2x+5
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Equation 8-5(2x-3)=13-6x
- Express {x} in terms of y where:
- -4*x+6*y=-7
- -7*x-13*y=5
- 6*x+1*y=14
- 14*x-3*y=-5
- Graphing y =:
- -4-6x
- 4x-3
- Derivative of:
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4x-3
- Integral of d{x}:
- 4x-3
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Identical expressions
- - four -6x=4x- three
- minus 4 minus 6x equally 4x minus 3
- minus four minus 6x equally 4x minus three
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Similar expressions
- 4^x-3*2^x+2=0
- 6x=1-(4-6x)
- -4+6x=4x-3
- -4-6*x=4*x-3
- (-4*x-3)*(x-3)=0
- -4-6x=4x+3
- 4-6x=4x-3
-4-6x=4x-3 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Move free summands (without x)
from left part to right part, we given:
$$- 6 x = 4 x + 1$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-10\right) x = 1$$
Divide both parts of the equation by -10
We get the answer: x = -1/10
-4-6*x = 4*x-3
Move free summands (without x)
from left part to right part, we given:
$$- 6 x = 4 x + 1$$
Move the summands with the unknown x
from the right part to the left part:
$$\left(-10\right) x = 1$$
Divide both parts of the equation by -10
x = 1 / (-10)
We get the answer: x = -1/10
Sum and product of roots
[src]
sum
-1/10
$$- \frac{1}{10}$$
=
-1/10
$$- \frac{1}{10}$$
product
-1/10
$$- \frac{1}{10}$$
=
-1/10
$$- \frac{1}{10}$$
-1/10
The graph