Mister Exam
Other calculators
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How to use it?
- Equation:
-
Equation x^3=3
-
Equation 5-x^2=0
- Equation (-5*x+3)*(-x+8)=0
-
Equation x^2+6=5x
- Express {x} in terms of y where:
- -6*x+11*y=-5
- -3*x-19*y=-9
- -19*x-15*y=15
- 16*x+14*y=-14
- Sum of series:
-
-1
- Derivative of:
-
-1
- Integral of d{x}:
-
-1
-
Identical expressions
- -|-x|=- one
- minus module of minus x| equally minus 1
- minus module of minus x| equally minus one
-
Similar expressions
- -|-x|=+1
- |-x|=-1
- -|+x|=-1
-|-x|=-1 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$1 - x = 0$$
after simplifying we get
$$1 - x = 0$$
the solution in this interval:
$$x_{1} = 1$$
2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$1 - - x = 0$$
after simplifying we get
$$x + 1 = 0$$
the solution in this interval:
$$x_{2} = -1$$
The final answer:
$$x_{1} = 1$$
$$x_{2} = -1$$
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$1 - x = 0$$
after simplifying we get
$$1 - x = 0$$
the solution in this interval:
$$x_{1} = 1$$
2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$1 - - x = 0$$
after simplifying we get
$$x + 1 = 0$$
the solution in this interval:
$$x_{2} = -1$$
The final answer:
$$x_{1} = 1$$
$$x_{2} = -1$$
The graph