Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 81*x^3+18*x^2+x=0
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Equation 6=8-5(7x-1)
-
Equation (-x-4)*(3*x+3)=0
- Equation x^2-144=0
- Express {x} in terms of y where:
- -14*x-8*y=20
- -1*x+4*y=-10
- 8*x+6*y=20
- -11*x-19*y=14
- Graphing y =:
- |-x|
- Sum of series:
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-1
- Derivative of:
-
-1
- Integral of d{x}:
-
-1
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Identical expressions
- |-x|=- one
- module of minus x| equally minus 1
- module of minus x| equally minus one
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Similar expressions
- 2*sin*|x-2|-x*|sinx|=0
- |+x|=-1
- |-x|=+1
|-x|=-1 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$x + 1 = 0$$
after simplifying we get
$$x + 1 = 0$$
the solution in this interval:
$$x_{1} = -1$$
but x1 not in the inequality interval
2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$1 - x = 0$$
after simplifying we get
$$1 - x = 0$$
the solution in this interval:
$$x_{2} = 1$$
but x2 not in the inequality interval
The final answer:
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$x + 1 = 0$$
after simplifying we get
$$x + 1 = 0$$
the solution in this interval:
$$x_{1} = -1$$
but x1 not in the inequality interval
2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$1 - x = 0$$
after simplifying we get
$$1 - x = 0$$
the solution in this interval:
$$x_{2} = 1$$
but x2 not in the inequality interval
The final answer:
The graph