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![log_2(4(x)^4+28)=2+log[sqrt[2],sqrt[5(x)^2+1]]](/media/krcore-image-pods/hash/equation/a/3b/2fd2cbe4331476c13922de3697e5d.png "Solve the equation log_2(4(x)⁴+28)=2+log[sqrt[2],sqrt[5(x)²+1]] (logarithm of _2(4(x) to the power of 4 plus 28) equally 2 plus logarithm of [ square root of [2], square root of [5(x) squared plus 1]]) - Find the roots of the equation in detail step by step. [THERE'S THE ANSWER!]")
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How to use it?
- Equation:
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Equation 14x-17+3x^2=19+11x
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![Equation log_2(4(x)^4+28)=2+log[sqrt[2],sqrt[5(x)^2+1]]](/media/krcore-image-pods/64/hash/equation/a/3b/2fd2cbe4331476c13922de3697e5d.png "Equation log_2(4(x)^4+28)=2+log[sqrt[2],sqrt[5(x)^2+1]]")
Equation log_2(4(x)^4+28)=2+log[sqrt[2],sqrt[5(x)^2+1]]
- Equation y:27=104
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Equation 78/97-x/97=11/97
- Express {x} in terms of y where:
- 60x^2y+75x^2y^2+120xy^260x2y+75x2y2+120xy2приx=-0,5x=−0,5,y=0,4y=0,4.
- (x-17)^2+(y+26)^2=16(x−17)2+(y+26)2=16.
- 5*x-5*y=20
- 8*x-7*y=-13
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Identical expressions
- log_ two (four (x)^ four + twenty-eight)= two +log[sqrt[ two ],sqrt[ five (x)^2+ one ]]
- logarithm of _2(4(x) to the power of 4 plus 28) equally 2 plus logarithm of [ square root of [2], square root of [5(x) squared plus 1]]
- logarithm of _ two (four (x) to the power of four plus twenty minus eight) equally two plus logarithm of [ square root of [ two ], square root of [ five (x) squared plus one ]]
- log_2(4(x)^4+28)=2+log[√[2],√[5(x)^2+1]]
- log_2(4(x)4+28)=2+log[sqrt[2],sqrt[5(x)2+1]]
- log_24x4+28=2+log[sqrt[2],sqrt[5x2+1]]
- log_2(4(x)⁴+28)=2+log[sqrt[2],sqrt[5(x)²+1]]
- log_2(4(x) to the power of 4+28)=2+log[sqrt[2],sqrt[5(x) to the power of 2+1]]
- log_24x^4+28=2+log[sqrt[2],sqrt[5x^2+1]]
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Similar expressions
- log_2(4(x)^4-28)=2+log[sqrt[2],sqrt[5(x)^2+1]]
- log_2(4(x)^4+28)=2+log[sqrt[2],sqrt[5(x)^2-1]]
- log_2(4(x)^4+28)=2-log[sqrt[2],sqrt[5(x)^2+1]]
log_2(4(x)^4+28)=2+log[sqrt[2],sqrt[5(x)^2+1]] equation
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The solution
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[src]
/ 4 \ / __________\
log\4*x + 28/ | ___ / 2 |
-------------- = 2 + log\\/ 2 , \/ 5*x + 1 /
log(2)
$$\frac{\log{\left(4 x^{4} + 28 \right)}}{\log{\left(2 \right)}} = \log{\left(\sqrt{2} \right)} + 2$$
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