Mister Exam
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How to use it?
- Equation:
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Equation cos*((pi(4x+48))/4)=-(sqrt(2)/2)
- Equation log7(3-x)=2log7(4)
- Equation 121p²+14p+2=0
- Equation lg(3x^2-17x+2)-lg(x^2-6x+1)=lg2
- Express {x} in terms of y where:
- (x^2+y^2-1)^3+x^2*y^3=0
- -1*x-19*y=-10
- 5*x+5*y=20
- 4*x-16*y=6
- Sum of series:
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lg2
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Identical expressions
- lg(3x^ two - one 7x+ two)-lg(x^ two -6x+1)=lg2
- lg(3x squared minus 17x plus 2) minus lg(x squared minus 6x plus 1) equally lg2
- lg(3x to the power of two minus one 7x plus two) minus lg(x to the power of two minus 6x plus 1) equally lg2
- lg(3x2-17x+2)-lg(x2-6x+1)=lg2
- lg3x2-17x+2-lgx2-6x+1=lg2
- lg(3x²-17x+2)-lg(x²-6x+1)=lg2
- lg(3x to the power of 2-17x+2)-lg(x to the power of 2-6x+1)=lg2
- lg3x^2-17x+2-lgx^2-6x+1=lg2
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Similar expressions
- lg(3x^2+17x+2)-lg(x^2-6x+1)=lg2
- lg(3x^2-17x+2)-lg(x^2+6x+1)=lg2
- lg^4(x^2-26)^4-4*lg^2(x^2-26)^2=240
- lg(3x^2-17x+2)+lg(x^2-6x+1)=lg2
- lg(3x^2-17x-2)-lg(x^2-6x+1)=lg2
- lg(3x^2-17x+2)-lg(x^2-6x-1)=lg2
- lg^2(x+1)=lg(x+1)*lg(x-1)+2lg^2(x-1)
- lg^2x+lgx^2=log2-1
- lg^(2)(x)=lg(10x)
lg(3x^2-17x+2)-lg(x^2-6x+1)=lg2 equation
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/ 2 \ / 2 \ log\3*x - 17*x + 2/ - log\x - 6*x + 1/ = log(2)
$$- \log{\left(\left(x^{2} - 6 x\right) + 1 \right)} + \log{\left(\left(3 x^{2} - 17 x\right) + 2 \right)} = \log{\left(2 \right)}$$