Mister Exam

Other calculators


k^2-1=0

k^2-1=0 equation

The teacher will be very surprised to see your correct solution 😉

v

Numerical solution:

Do search numerical solution at [, ]

The solution

You have entered [src]
 2        
k  - 1 = 0
k21=0k^{2} - 1 = 0
Detail solution
This equation is of the form
a*k^2 + b*k + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
k1=Db2ak_{1} = \frac{\sqrt{D} - b}{2 a}
k2=Db2ak_{2} = \frac{- \sqrt{D} - b}{2 a}
where D = b^2 - 4*a*c - it is the discriminant.
Because
a=1a = 1
b=0b = 0
c=1c = -1
, then
D = b^2 - 4 * a * c = 

(0)^2 - 4 * (1) * (-1) = 4

Because D > 0, then the equation has two roots.
k1 = (-b + sqrt(D)) / (2*a)

k2 = (-b - sqrt(D)) / (2*a)

or
k1=1k_{1} = 1
k2=1k_{2} = -1
Vieta's Theorem
it is reduced quadratic equation
k2+kp+q=0k^{2} + k p + q = 0
where
p=bap = \frac{b}{a}
p=0p = 0
q=caq = \frac{c}{a}
q=1q = -1
Vieta Formulas
k1+k2=pk_{1} + k_{2} = - p
k1k2=qk_{1} k_{2} = q
k1+k2=0k_{1} + k_{2} = 0
k1k2=1k_{1} k_{2} = -1
The graph
05-15-10-51015200-100
Sum and product of roots [src]
sum
-1 + 1
1+1-1 + 1
=
0
00
product
-1
1-1
=
-1
1-1
-1
Rapid solution [src]
k1 = -1
k1=1k_{1} = -1
k2 = 1
k2=1k_{2} = 1
k2 = 1
Numerical answer [src]
k1 = 1.0
k2 = -1.0
k2 = -1.0
The graph
k^2-1=0 equation