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- Equation:
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Equation (x-4)^2+(x+9)^2=2x^2
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Equation (x-5)^2=(x-8)^2
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Equation sin(x)=-1/4
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Equation tg(x)=-1/2
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- 14*x-16*y=14
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- 4*x+13*y=13
- 17*x-19*y=1
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Identical expressions
- five (two -5x)- seven (4x- one)=6x- forty-two
- 5(2 minus 5x) minus 7(4x minus 1) equally 6x minus 42
- five (two minus 5x) minus seven (4x minus one) equally 6x minus forty minus two
- 52-5x-74x-1=6x-42
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Similar expressions
- 5(2+5x)-7(4x-1)=6x-42
- 36*x-42=48x
- (x+6)*(x-4)*2=0
- (x+6)(x-4)*2=0
- 5(2-5x)-7(4x+1)=6x-42
- 5(2-5x)-7(4x-1)=6x+42
- 2x-11=6x-4*(2x-1)
- 5(2-5x)+7(4x-1)=6x-42
5(2-5x)-7(4x-1)=6x-42 equation
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The solution
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5*(2 - 5*x) - 7*(4*x - 1) = 6*x - 42
$$5 \cdot \left(- 5 x + 2\right) - 7 \cdot \left(4 x - 1\right) = 6 x - 42$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 53 x = 6 x - 59$$
Move the summands with the unknown x
from the right part to the left part:
$$- 59 x = -59$$
Divide both parts of the equation by -59
We get the answer: x = 1
5*(2-5*x)-7*(4*x-1) = 6*x-42
Expand brackets in the left part
5*2-5*5*x-7*4*x+7*1 = 6*x-42
Looking for similar summands in the left part:
17 - 53*x = 6*x-42
Move free summands (without x)
from left part to right part, we given:
$$- 53 x = 6 x - 59$$
Move the summands with the unknown x
from the right part to the left part:
$$- 59 x = -59$$
Divide both parts of the equation by -59
x = -59 / (-59)
We get the answer: x = 1
The graph