Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 2x-3(x+3)=-5
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Equation x^2-4x+4=0
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Equation sin(x)=1/5
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Equation x^2+3x+2=0
- Express {x} in terms of y where:
- -17*x+2*y=-4
- -13*x+7*y=-15
- -4*x-8*y=-20
- -9*x+11*y=9
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Identical expressions
- 2x- eleven =6x- four *(2x- one)
- 2x minus 11 equally 6x minus 4 multiply by (2x minus 1)
- 2x minus eleven equally 6x minus four multiply by (2x minus one)
- 2x-11=6x-4(2x-1)
- 2x-11=6x-42x-1
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Similar expressions
- 9(x-9)+11(x-11)-2(x-11)(x-9)=0
- 2x-11=6x-4*(2x+1)
- (2*x-1)^(1/2)=0
- 2x-11=6x+4*(2x-1)
- 2x+11=6x-4*(2x-1)
- log(6)*(x-1)+log(6)*(2*x-11)=log(6)*2
- x-4/3+2*(x+1)/4-1=5*(x-3)/2+2*x-11*x+43/6
2x-11=6x-4*(2x-1) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$2 x = 15 - 2 x$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = 15$$
Divide both parts of the equation by 4
We get the answer: x = 15/4
2*x-11 = 6*x-4*(2*x-1)
Expand brackets in the right part
2*x-11 = 6*x-4*2*x+4*1
Looking for similar summands in the right part:
-11 + 2*x = 4 - 2*x
Move free summands (without x)
from left part to right part, we given:
$$2 x = 15 - 2 x$$
Move the summands with the unknown x
from the right part to the left part:
$$4 x = 15$$
Divide both parts of the equation by 4
x = 15 / (4)
We get the answer: x = 15/4
Sum and product of roots
[src]
sum
15/4
$$\frac{15}{4}$$
=
15/4
$$\frac{15}{4}$$
product
15/4
$$\frac{15}{4}$$
=
15/4
$$\frac{15}{4}$$
15/4