Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 81*x^3+18*x^2+x=0
-
Equation 6=8-5(7x-1)
-
Equation 3x=28-x
-
Equation 3x=2
- Express {x} in terms of y where:
- -13*x-7*y=16
- -16*x+10*y=-11
- -2*x-15*y=-1
- -14*x+5*y=-1
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Identical expressions
- (x+ six)*(x- four)* two = zero
- (x plus 6) multiply by (x minus 4) multiply by 2 equally 0
- (x plus six) multiply by (x minus four) multiply by two equally zero
- (x+6)(x-4)2=0
- x+6x-42=0
- (x+6)*(x-4)*2=O
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Similar expressions
- (x+6)*(x+4)*2=0
- (x-6)*(x-4)*2=0
(x+6)*(x-4)*2=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Expand the expression in the equation
$$2 \left(x - 4\right) \left(x + 6\right) = 0$$
We get the quadratic equation
$$2 x^{2} + 4 x - 48 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 2$$
$$b = 4$$
$$c = -48$$
, then
Because D > 0, then the equation has two roots.
or
$$x_{1} = 4$$
$$x_{2} = -6$$
$$2 \left(x - 4\right) \left(x + 6\right) = 0$$
We get the quadratic equation
$$2 x^{2} + 4 x - 48 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 2$$
$$b = 4$$
$$c = -48$$
, then
D = b^2 - 4 * a * c =
(4)^2 - 4 * (2) * (-48) = 400
Because D > 0, then the equation has two roots.
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
or
$$x_{1} = 4$$
$$x_{2} = -6$$
Sum and product of roots
[src]
sum
-6 + 4
$$-6 + 4$$
=
-2
$$-2$$
product
-6*4
$$- 24$$
=
-24
$$-24$$
-24