abs(abs(x)+3)=4+x equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
For every modulo expressions in the equation
allow cases, when this expressions ">=0" or "<0",
solve the resulting equation.
1.
$$x \geq 0$$
or
$$0 \leq x \wedge x < \infty$$
we get the equation
$$- x + x - 1 = 0$$
after simplifying we get
incorrect
the solution in this interval:
2.
$$x < 0$$
or
$$-\infty < x \wedge x < 0$$
we get the equation
$$- x - x - 1 = 0$$
after simplifying we get
$$- 2 x - 1 = 0$$
the solution in this interval:
$$x_{1} = - \frac{1}{2}$$
The final answer:
$$x_{1} = - \frac{1}{2}$$
$$x_{1} = - \frac{1}{2}$$
Sum and product of roots
[src]
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$