Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation cos(x)-1=0
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Equation 4x+9=5(2x-7)-6x
- Equation x^(2)-4*x+y^(2)+3=0
- Equation 8⋅(8+y)−5y=4y−63.
- Express {x} in terms of y where:
- lnx^y=ln1
- 12*10^(-30)-0,1884*10^12*x^2-y(0,3768*10^12*x+1,183152*10^12*x^3)+y^2(2,760688*10^24*x^2)=0=0
- (x^2+y^2)×(x+y-3)=2xy
- sqrt(1-x)^2+(4-y)^2=0
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Identical expressions
- eight ⋅(eight +y)−5y=4y− sixty-three .
- 8⋅(8 plus y)−5y equally 4y−63.
- eight ⋅(eight plus y)−5y equally 4y− sixty minus three .
- 8⋅8+y−5y=4y−63.
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Similar expressions
- 8⋅(8-y)−5y=4y−63.
8⋅(8+y)−5y=4y−63. equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without y)
from left part to right part, we given:
$$3 y = 4 y - 127$$
Move the summands with the unknown y
from the right part to the left part:
$$- y = -127$$
Divide both parts of the equation by -1
We get the answer: y = 127
8*(8+y)-5*y = 4*y-63
Expand brackets in the left part
8*8+8*y-5*y = 4*y-63
Looking for similar summands in the left part:
64 + 3*y = 4*y-63
Move free summands (without y)
from left part to right part, we given:
$$3 y = 4 y - 127$$
Move the summands with the unknown y
from the right part to the left part:
$$- y = -127$$
Divide both parts of the equation by -1
y = -127 / (-1)
We get the answer: y = 127