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4+x

Limit of the function 4+x

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 lim (4 + x)
x->5+       
$$\lim_{x \to 5^+}\left(x + 4\right)$$
Limit(4 + x, x, 5)
Lopital's rule
There is no sense to apply Lopital's rule to this function since there is no indeterminateness of 0/0 or oo/oo type
The graph
Other limits x→0, -oo, +oo, 1
$$\lim_{x \to 5^-}\left(x + 4\right) = 9$$
More at x→5 from the left
$$\lim_{x \to 5^+}\left(x + 4\right) = 9$$
$$\lim_{x \to \infty}\left(x + 4\right) = \infty$$
More at x→oo
$$\lim_{x \to 0^-}\left(x + 4\right) = 4$$
More at x→0 from the left
$$\lim_{x \to 0^+}\left(x + 4\right) = 4$$
More at x→0 from the right
$$\lim_{x \to 1^-}\left(x + 4\right) = 5$$
More at x→1 from the left
$$\lim_{x \to 1^+}\left(x + 4\right) = 5$$
More at x→1 from the right
$$\lim_{x \to -\infty}\left(x + 4\right) = -\infty$$
More at x→-oo
One‐sided limits [src]
 lim (4 + x)
x->5+       
$$\lim_{x \to 5^+}\left(x + 4\right)$$
9
$$9$$
= 9.0
 lim (4 + x)
x->5-       
$$\lim_{x \to 5^-}\left(x + 4\right)$$
9
$$9$$
= 9.0
= 9.0
Rapid solution [src]
9
$$9$$
Numerical answer [src]
9.0
9.0
The graph
Limit of the function 4+x