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a^2+10*a+25+(a+5)*(5-a) equation

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Numerical solution:

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The solution

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 2                                  
a  + 10*a + 25 + (a + 5)*(5 - a) = 0
$$\left(5 - a\right) \left(a + 5\right) + \left(\left(a^{2} + 10 a\right) + 25\right) = 0$$
Detail solution
Given the equation:
a^2+10*a+25+(a+5)*(5-a) = 0

Expand expressions:
a^2 + 10*a + 25 + 25 - a^2 = 0

Reducing, you get:
50 + 10*a = 0

Move free summands (without a)
from left part to right part, we given:
$$10 a = -50$$
Divide both parts of the equation by 10
a = -50 / (10)

We get the answer: a = -5
The graph
Rapid solution [src]
a1 = -5
$$a_{1} = -5$$
a1 = -5
Sum and product of roots [src]
sum
-5
$$-5$$
=
-5
$$-5$$
product
-5
$$-5$$
=
-5
$$-5$$
-5
Numerical answer [src]
a1 = -5.0
a1 = -5.0