a^2+10*a+25+(a+5)*(5-a) equation
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The solution
Detail solution
Given the equation:
a^2+10*a+25+(a+5)*(5-a) = 0
Expand expressions:
a^2 + 10*a + 25 + 25 - a^2 = 0
Reducing, you get:
50 + 10*a = 0
Move free summands (without a)
from left part to right part, we given:
$$10 a = -50$$
Divide both parts of the equation by 10
a = -50 / (10)
We get the answer: a = -5
Sum and product of roots
[src]
$$-5$$
$$-5$$
$$-5$$
$$-5$$