а²+6а+9+(а+3)(3-а) equation
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The solution
Detail solution
Given the equation:
a^2+6*a+9+(a+3)*(3-a) = 0
Expand expressions:
a^2 + 6*a + 9 + 9 - a^2 = 0
Reducing, you get:
18 + 6*a = 0
Move free summands (without a)
from left part to right part, we given:
$$6 a = -18$$
Divide both parts of the equation by 6
a = -18 / (6)
We get the answer: a = -3
Sum and product of roots
[src]
$$\left(-3\right)$$
$$-3$$
$$\left(-3\right)$$
$$-3$$