Move right part of the equation to
left part with negative sign.
The equation is transformed from
$$3 x^{2} + 9 x - 25 = 2 x^{2} + 8 x + 17$$
to
$$\left(- 2 x^{2} - 8 x - 17\right) + \left(3 x^{2} + 9 x - 25\right) = 0$$
This equation is of the form
$$a\ x^2 + b\ x + c = 0$$
A quadratic equation can be solved using the discriminant
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where $D = b^2 - 4 a c$ is the discriminant.
Because
$$a = 1$$
$$b = 1$$
$$c = -42$$
, then
$$D = b^2 - 4\ a\ c = $$
$$1^{2} - 1 \cdot 4 \left(-42\right) = 169$$
Because D > 0, then the equation has two roots.
$$x_1 = \frac{(-b + \sqrt{D})}{2 a}$$
$$x_2 = \frac{(-b - \sqrt{D})}{2 a}$$
or
$$x_{1} = 6$$
Simplify$$x_{2} = -7$$
Simplify