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- Equation:
-
Equation 9x-6(x-1)=5(x+2)
-
Equation (-x-5)(2x+4)=0
-
Equation k^2-2*k+2=0
-
Equation k^2-4*k+3=0
- Express {x} in terms of y where:
- 8*x+7*y=-13
- -4*x+18*y=-14
- 14*x-16*y=14
- -10*x+18*y=6
-
Identical expressions
- 9x- six (x- one)= five (x+ two)
- 9x minus 6(x minus 1) equally 5(x plus 2)
- 9x minus six (x minus one) equally five (x plus two)
- 9x-6x-1=5x+2
-
Similar expressions
- (3x-8)^2-(4x+6)^2+(5x-2)(5x+2)=96
- 9*x-6(x-1)=5(x+2)
- 4*(5x+2)=10*(2x-3)+15
- 9x+6(x-1)=5(x+2)
- 5x+2=18-3x
- 9x-6(x+1)=5(x+2)
- x^2+2*5x+25=0
- 9x-6(x-1)=5(x-2)
9x-6(x-1)=5(x+2) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
9*x - 6*(x - 1) = 5*(x + 2)
$$9 x - 6 \left(x - 1\right) = 5 \left(x + 2\right)$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Expand brackets in the right part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$3 x = 5 x + 4$$
Move the summands with the unknown x
from the right part to the left part:
$$- 2 x = 4$$
Divide both parts of the equation by -2
We get the answer: x = -2
9*x-6*(x-1) = 5*(x+2)
Expand brackets in the left part
9*x-6*x+6*1 = 5*(x+2)
Expand brackets in the right part
9*x-6*x+6*1 = 5*x+5*2
Looking for similar summands in the left part:
6 + 3*x = 5*x+5*2
Move free summands (without x)
from left part to right part, we given:
$$3 x = 5 x + 4$$
Move the summands with the unknown x
from the right part to the left part:
$$- 2 x = 4$$
Divide both parts of the equation by -2
x = 4 / (-2)
We get the answer: x = -2
Sum and product of roots
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sum
-2
$$\left(-2\right)$$
=
-2
$$-2$$
product
-2
$$\left(-2\right)$$
=
-2
$$-2$$
The graph