Given the equation:
$$7 x^{3} - 28 x = 0$$
transform
Take common factor $x$ from the equation
we get:
$$x \left(7 x^{2} - 28\right) = 0$$
then:
$$x_{1} = 0$$
and also
we get the equation
$$7 x^{2} - 28 = 0$$
This equation is of the form
$$a\ x^2 + b\ x + c = 0$$
A quadratic equation can be solved using the discriminant
The roots of the quadratic equation:
$$x_{2} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{3} = \frac{- \sqrt{D} - b}{2 a}$$
where $D = b^2 - 4 a c$ is the discriminant.
Because
$$a = 7$$
$$b = 0$$
$$c = -28$$
, then
$$D = b^2 - 4\ a\ c = $$
$$0^{2} - 7 \cdot 4 \left(-28\right) = 784$$
Because D > 0, then the equation has two roots.
$$x_2 = \frac{(-b + \sqrt{D})}{2 a}$$
$$x_3 = \frac{(-b - \sqrt{D})}{2 a}$$
or
$$x_{2} = 2$$
Simplify$$x_{3} = -2$$
SimplifyThe final answer for (7*x^3 - 28*x) + 0 = 0:
$$x_{1} = 0$$
$$x_{2} = 2$$
$$x_{3} = -2$$