Mister Exam
Other calculators
-
How to use it?
- Express {x} in terms of y where:
- -12*x+3*y=-9
- -10*x-16*y=-6
- 16*x+7*y=8
- -11*x+4*y=-8
- Equation:
-
Equation 3(4-2x)+6=-2x+4
- Equation 9x^2-45x=0
-
Equation 25x^2=16
-
Equation log(x)+1=0
- Limit of the function:
-
-9
- Integral of d{x}:
- -9
-
Identical expressions
- - twelve *x+ three *y=- nine
- minus 12 multiply by x plus 3 multiply by y equally minus 9
- minus twelve multiply by x plus three multiply by y equally minus nine
- -12x+3y=-9
-
Similar expressions
- -12*x+3*y=+9
- 12*x+3*y=-9
- -12*x-3*y=-9
Express x in terms of y where -12*x+3*y=-9
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 12 x = - 3 y - 9$$
Divide both parts of the equation by -12
We get the answer: x = 3/4 + y/4
-12*x+3*y = -9
Looking for similar summands in the left part:
-12*x + 3*y = -9
Move the summands with the other variables
from left part to right part, we given:
$$- 12 x = - 3 y - 9$$
Divide both parts of the equation by -12
x = -9 - 3*y / (-12)
We get the answer: x = 3/4 + y/4
Rapid solution
[src]
3 re(y) I*im(y)
x1 = - + ----- + -------
4 4 4
$$x_{1} = \frac{\operatorname{re}{\left(y\right)}}{4} + \frac{i \operatorname{im}{\left(y\right)}}{4} + \frac{3}{4}$$
x1 = re(y)/4 + i*im(y)/4 + 3/4