cos(x)=2 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the equation
cos(x)=2- this is the simplest trigonometric equation
As right part of the equation
modulo =
True
but cos
can no be more than 1 or less than -1
so the solution of the equation d'not exist.
The graph
x1 = 2*pi - I*im(acos(2))
x1=2π−iim(acos(2))
x2 = I*im(acos(2)) + re(acos(2))
x2=re(acos(2))+iim(acos(2))
Sum and product of roots
[src]
0 + 2*pi - I*im(acos(2)) + I*im(acos(2)) + re(acos(2))
(0+(2π−iim(acos(2))))+(re(acos(2))+iim(acos(2)))
re(acos(2))+2π
1*(2*pi - I*im(acos(2)))*(I*im(acos(2)) + re(acos(2)))
1⋅(2π−iim(acos(2)))(re(acos(2))+iim(acos(2)))
(2*pi - I*im(acos(2)))*(I*im(acos(2)) + re(acos(2)))
(2π−iim(acos(2)))(re(acos(2))+iim(acos(2)))
(2*pi - i*im(acos(2)))*(i*im(acos(2)) + re(acos(2)))
x1 = 6.28318530717959 - 1.31695789692482*i