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cos(x)=2

cos(x)=2 equation

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Numerical solution:

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The solution

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cos(x) = 2
$$\cos{\left(x \right)} = 2$$
Detail solution
Given the equation
$$\cos{\left(x \right)} = 2$$
- this is the simplest trigonometric equation
As right part of the equation
modulo =
True

but cos
can no be more than 1 or less than -1
so the solution of the equation d'not exist.
The graph
Rapid solution [src]
x1 = 2*pi - I*im(acos(2))
$$x_{1} = 2 \pi - i \operatorname{im}{\left(\operatorname{acos}{\left(2 \right)}\right)}$$
x2 = I*im(acos(2)) + re(acos(2))
$$x_{2} = \operatorname{re}{\left(\operatorname{acos}{\left(2 \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(2 \right)}\right)}$$
Sum and product of roots [src]
sum
0 + 2*pi - I*im(acos(2)) + I*im(acos(2)) + re(acos(2))
$$\left(0 + \left(2 \pi - i \operatorname{im}{\left(\operatorname{acos}{\left(2 \right)}\right)}\right)\right) + \left(\operatorname{re}{\left(\operatorname{acos}{\left(2 \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(2 \right)}\right)}\right)$$
=
2*pi + re(acos(2))
$$\operatorname{re}{\left(\operatorname{acos}{\left(2 \right)}\right)} + 2 \pi$$
product
1*(2*pi - I*im(acos(2)))*(I*im(acos(2)) + re(acos(2)))
$$1 \cdot \left(2 \pi - i \operatorname{im}{\left(\operatorname{acos}{\left(2 \right)}\right)}\right) \left(\operatorname{re}{\left(\operatorname{acos}{\left(2 \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(2 \right)}\right)}\right)$$
=
(2*pi - I*im(acos(2)))*(I*im(acos(2)) + re(acos(2)))
$$\left(2 \pi - i \operatorname{im}{\left(\operatorname{acos}{\left(2 \right)}\right)}\right) \left(\operatorname{re}{\left(\operatorname{acos}{\left(2 \right)}\right)} + i \operatorname{im}{\left(\operatorname{acos}{\left(2 \right)}\right)}\right)$$
(2*pi - i*im(acos(2)))*(i*im(acos(2)) + re(acos(2)))
Numerical answer [src]
x1 = 6.28318530717959 - 1.31695789692482*i
x2 = 1.31695789692482*i
x2 = 1.31695789692482*i
The graph
cos(x)=2 equation