Mister Exam
Other calculators
-
How to use it?
- Equation:
-
Equation 25*x^3-10*x^2+x=0
-
Equation 2x^2-x-1=x^2-5x-(-1-x^2)
-
Equation 2^x=5
-
Equation (x-10)^2=(x+4)^2
- Express {x} in terms of y where:
- 15*x+12*y=-19
- -19*x-20*y=-4
- -18*x+12*y=-8
- -14*x+4*y=-16
-
Identical expressions
- (7x- one)-(9x+ three)= five
- (7x minus 1) minus (9x plus 3) equally 5
- (7x minus one) minus (9x plus three) equally five
- 7x-1-9x+3=5
-
Similar expressions
- (7x+1)-(9x+3)=5
- (7x-1)+(9x+3)=5
- (7x-1)-(9x-3)=5
(7x-1)-(9x+3)=5 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = 9$$
Divide both parts of the equation by -2
We get the answer: x = -9/2
(7*x-1)-(9*x+3) = 5
Expand brackets in the left part
7*x-1-9*x-3 = 5
Looking for similar summands in the left part:
-4 - 2*x = 5
Move free summands (without x)
from left part to right part, we given:
$$- 2 x = 9$$
Divide both parts of the equation by -2
x = 9 / (-2)
We get the answer: x = -9/2
Sum and product of roots
[src]
sum
-9/2
$$- \frac{9}{2}$$
=
-9/2
$$- \frac{9}{2}$$
product
-9/2
$$- \frac{9}{2}$$
=
-9/2
$$- \frac{9}{2}$$
-9/2