Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation 7x-15=4x-3(x-3)
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Equation log3(5-x)+log3(-1-x)=3
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Equation log(27)*x=1/3
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Equation 2x^2+13-13x=x+1
- Express {x} in terms of y where:
- 15*x+15*y=16
- -4*x+18*y=-14
- 8*x+7*y=-13
- 14*x-16*y=14
- Graphing y =:
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7x-15
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Identical expressions
- 7x- fifteen =4x- three (x- three)
- 7x minus 15 equally 4x minus 3(x minus 3)
- 7x minus fifteen equally 4x minus three (x minus three)
- 7x-15=4x-3x-3
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Similar expressions
- (-4x-3)(x-3)=0
- 4*(x-3)*(x-3)=0
- 7x-15=4x-3(x+3)
- (x^2-x)/(x^2-9)=(7*x-15)/(x^2-9)
- (2*x^2-7*x-15)*(2*sin(x)-sqrt(3))=0
- 8*x+9=4-5*x-7*x-15
- (-4x-3)*(x-3)=0
- (-4*x-3)*(x-3)=0
- 7x+15=4x-3(x-3)
- 7x-15=4x+3(x-3)
7x-15=4x-3(x-3) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
Move the summands with the unknown x
from the right part to the left part:
Divide both parts of the equation by 6
We get the answer: x = 4
7*x-15 = 4*x-3*(x-3)
Expand brackets in the right part
7*x-15 = 4*x-3*x+3*3
Looking for similar summands in the right part:
-15 + 7*x = 9 + x
Move free summands (without x)
from left part to right part, we given:
Move the summands with the unknown x
from the right part to the left part:
Divide both parts of the equation by 6
x = 24 / (6)
We get the answer: x = 4
The graph