Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation -x/12+x=55/12
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Equation 9/(x-2)=9/2
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Equation 2-3*(2*x+2)=5-4*x
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Equation x^4=(4x-21)^2
- Express {x} in terms of y where:
- 4*x+2*y=5
- -10*x-18*y=15
- 2*x-8*y=4
- 2*x-15*y=-1
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Identical expressions
- four *(x- three)*(x- three)= zero
- 4 multiply by (x minus 3) multiply by (x minus 3) equally 0
- four multiply by (x minus three) multiply by (x minus three) equally zero
- 4(x-3)(x-3)=0
- 4x-3x-3=0
- 4*(x-3)*(x-3)=O
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Similar expressions
- 7x—15=4x-3(x-3)
- 4*(x+3)*(x-3)=0
- 4*(x-3)*(x+3)=0
4*(x-3)*(x-3)=0 equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Expand the expression in the equation
$$\left(x - 3\right) 4 \left(x - 3\right) = 0$$
We get the quadratic equation
$$4 x^{2} - 24 x + 36 = 0$$
This equation is of the form
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 4$$
$$b = -24$$
$$c = 36$$
, then
Because D = 0, then the equation has one root.
$$x_{1} = 3$$
$$\left(x - 3\right) 4 \left(x - 3\right) = 0$$
We get the quadratic equation
$$4 x^{2} - 24 x + 36 = 0$$
This equation is of the form
a*x^2 + b*x + c = 0
A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$x_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$x_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 4$$
$$b = -24$$
$$c = 36$$
, then
D = b^2 - 4 * a * c =
(-24)^2 - 4 * (4) * (36) = 0
Because D = 0, then the equation has one root.
x = -b/2a = --24/2/(4)
$$x_{1} = 3$$