4y+7/2y-3-y-3/2y-3=1 equation
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The solution
Detail solution
Given the linear equation:
4*y+7/2*y-3-y-3/2*y-3 = 1
Looking for similar summands in the left part:
-6 + 5*y = 1
Move free summands (without y)
from left part to right part, we given:
$$5 y = 7$$
Divide both parts of the equation by 5
y = 7 / (5)
We get the answer: y = 7/5
Sum and product of roots
[src]
$$\frac{7}{5}$$
$$\frac{7}{5}$$
$$\frac{7}{5}$$
$$\frac{7}{5}$$