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4y+7/2y-3-y-3/2y-3=1 equation

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Numerical solution:

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The solution

You have entered [src]
      7*y           3*y        
4*y + --- - 3 - y - --- - 3 = 1
       2             2         
$$\left(- \frac{3 y}{2} + \left(- y + \left(\left(\frac{7 y}{2} + 4 y\right) - 3\right)\right)\right) - 3 = 1$$
Detail solution
Given the linear equation:
4*y+7/2*y-3-y-3/2*y-3 = 1

Looking for similar summands in the left part:
-6 + 5*y = 1

Move free summands (without y)
from left part to right part, we given:
$$5 y = 7$$
Divide both parts of the equation by 5
y = 7 / (5)

We get the answer: y = 7/5
The graph
Rapid solution [src]
y1 = 7/5
$$y_{1} = \frac{7}{5}$$
y1 = 7/5
Sum and product of roots [src]
sum
7/5
$$\frac{7}{5}$$
=
7/5
$$\frac{7}{5}$$
product
7/5
$$\frac{7}{5}$$
=
7/5
$$\frac{7}{5}$$
7/5
Numerical answer [src]
y1 = 1.4
y1 = 1.4