Mister Exam
Other calculators
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How to use it?
- Equation:
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Equation tan(x)=-sqrt(3)/3
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Equation 3x-11=6x-4(2x-1)
- Equation (x^2-16)^2+(x^2+5x-36)^2=0
-
Equation tan(x)=0.8
- Express {x} in terms of y where:
- sqrt(x^2+y^2+4x-6y-12)+(x^2+10x-27)=8-|y-9|+|y-3|
- 10*x-1*y=10
- 15*x-17*y=19
- 9*x-8*y=6
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Identical expressions
- 3x- eleven =6x- four (2x- one)
- 3x minus 11 equally 6x minus 4(2x minus 1)
- 3x minus eleven equally 6x minus four (2x minus one)
- 3x-11=6x-42x-1
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Similar expressions
- 3x+11=6x-4(2x-1)
- 27(1/3x-1)(1/9x^2+1/3x+1)-x(x-1)(x+1)=2x^2
- 4-4*(x-3)*(3*x-11)=0
- 5*x-3=3*x-11
- 2x-11=6x-4*(2x-1)
- 3x-11=6x+4(2x-1)
- 3x-11=6x-4(2x+1)
3x-11=6x-4(2x-1) equation
The teacher will be very surprised to see your correct solution 😉
The solution
You have entered
[src]
3*x - 11 = 6*x - 4*(2*x - 1)
$$3 x - 11 = 6 x - 4 \cdot \left(2 x - 1\right)$$
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$3 x = - 2 x + 15$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = 15$$
Divide both parts of the equation by 5
We get the answer: x = 3
3*x-11 = 6*x-4*(2*x-1)
Expand brackets in the right part
3*x-11 = 6*x-4*2*x+4*1
Looking for similar summands in the right part:
-11 + 3*x = 4 - 2*x
Move free summands (without x)
from left part to right part, we given:
$$3 x = - 2 x + 15$$
Move the summands with the unknown x
from the right part to the left part:
$$5 x = 15$$
Divide both parts of the equation by 5
x = 15 / (5)
We get the answer: x = 3
Sum and product of roots
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sum
3
$$\left(3\right)$$
=
3
$$3$$
product
3
$$\left(3\right)$$
=
3
$$3$$
The graph