Move right part of the equation to left part with negative sign.
The equation is transformed from 3x2+14x−17=11x+19 to (−11x−19)+(3x2+14x−17)=0 This equation is of the form ax2+bx+c=0 A quadratic equation can be solved using the discriminant The roots of the quadratic equation: x1=2aD−b x2=2a−D−b where D=b2−4ac is the discriminant. Because a=3 b=3 c=−36 , then D=b2−4ac= 32−3⋅4(−36)=441 Because D > 0, then the equation has two roots. x1=2a(−b+D) x2=2a(−b−D) or x1=3 Simplify x2=−4 Simplify
Vieta's Theorem
rewrite the equation 3x2+14x−17=11x+19 of ax2+bx+c=0 as reduced quadratic equation x2+abx+ac=0 x2+x−12=0 px+x2+q=0 where p=ab p=1 q=ac q=−12 Vieta Formulas x1+x2=−p x1x2=q x1+x2=−1 x1x2=−12