Derivative of y=x^3(x^2-5)

1. Apply the product rule:

   $$\frac{d}{d x} f{\left(x \right)} g{\left(x \right)} = f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}$$

   $f{\left(x \right)} = x^{3}$; to find $\frac{d}{d x} f{\left(x \right)}$:

   1. Apply the power rule: $x^{3}$ goes to $3 x^{2}$

   $g{\left(x \right)} = x^{2} - 5$; to find $\frac{d}{d x} g{\left(x \right)}$:

   1. Differentiate $x^{2} - 5$ term by term:

      1. Apply the power rule: $x^{2}$ goes to $2 x$

      2. The derivative of the constant $\left(-1\right) 5$ is zero.

      The result is: $2 x$

   The result is: $2 x^{4} + 3 x^{2} \left(x^{2} - 5\right)$

2. Now simplify:

   $$5 x^{2} \left(x^{2} - 3\right)$$

The answer is: