Detail solution
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Apply the product rule:
; to find :
-
; to find :
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The derivative of cosine is negative sine:
The result is:
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Now simplify:
The answer is:
The first derivative
[src]
x x
- 2 *sin(x) + 2 *cos(x)*log(2)
$$- 2^{x} \sin{\left(x \right)} + 2^{x} \log{\left(2 \right)} \cos{\left(x \right)}$$
The second derivative
[src]
x / 2 \
2 *\-cos(x) + log (2)*cos(x) - 2*log(2)*sin(x)/
$$2^{x} \left(- 2 \log{\left(2 \right)} \sin{\left(x \right)} - \cos{\left(x \right)} + \log{\left(2 \right)}^{2} \cos{\left(x \right)}\right)$$
The third derivative
[src]
x / 3 2 \
2 *\log (2)*cos(x) - 3*log (2)*sin(x) - 3*cos(x)*log(2) + sin(x)/
$$2^{x} \left(- 3 \log{\left(2 \right)}^{2} \sin{\left(x \right)} + \sin{\left(x \right)} - 3 \log{\left(2 \right)} \cos{\left(x \right)} + \log{\left(2 \right)}^{3} \cos{\left(x \right)}\right)$$