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y=e^2x*(lnx+x^2)

Derivative of y=e^2x*(lnx+x^2)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 2   /          2\
E *x*\log(x) + x /
$$e^{2} x \left(x^{2} + \log{\left(x \right)}\right)$$
(E^2*x)*(log(x) + x^2)
Detail solution
  1. Apply the product rule:

    ; to find :

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Apply the power rule: goes to

      So, the result is:

    ; to find :

    1. Differentiate term by term:

      1. The derivative of is .

      2. Apply the power rule: goes to

      The result is:

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
/          2\  2     /1      \  2
\log(x) + x /*e  + x*|- + 2*x|*e 
                     \x      /   
$$x \left(2 x + \frac{1}{x}\right) e^{2} + \left(x^{2} + \log{\left(x \right)}\right) e^{2}$$
The second derivative [src]
/2           /    1 \\  2
|- + 4*x + x*|2 - --||*e 
|x           |     2||   
\            \    x //   
$$\left(x \left(2 - \frac{1}{x^{2}}\right) + 4 x + \frac{2}{x}\right) e^{2}$$
The third derivative [src]
/    1 \  2
|6 - --|*e 
|     2|   
\    x /   
$$\left(6 - \frac{1}{x^{2}}\right) e^{2}$$
The graph
Derivative of y=e^2x*(lnx+x^2)