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y=e^(cosx^2)

Derivative of y=e^(cosx^2)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
    2   
 cos (x)
e       
$$e^{\cos^{2}{\left(x \right)}}$$
  /    2   \
d | cos (x)|
--\e       /
dx          
$$\frac{d}{d x} e^{\cos^{2}{\left(x \right)}}$$
Detail solution
  1. Let .

  2. The derivative of is itself.

  3. Then, apply the chain rule. Multiply by :

    1. Let .

    2. Apply the power rule: goes to

    3. Then, apply the chain rule. Multiply by :

      1. The derivative of cosine is negative sine:

      The result of the chain rule is:

    The result of the chain rule is:

  4. Now simplify:


The answer is:

The graph
The first derivative [src]
              2          
           cos (x)       
-2*cos(x)*e       *sin(x)
$$- 2 e^{\cos^{2}{\left(x \right)}} \sin{\left(x \right)} \cos{\left(x \right)}$$
The second derivative [src]
                                              2   
  /   2         2           2       2   \  cos (x)
2*\sin (x) - cos (x) + 2*cos (x)*sin (x)/*e       
$$2 \cdot \left(2 \sin^{2}{\left(x \right)} \cos^{2}{\left(x \right)} + \sin^{2}{\left(x \right)} - \cos^{2}{\left(x \right)}\right) e^{\cos^{2}{\left(x \right)}}$$
The third derivative [src]
                                                             2          
  /         2           2           2       2   \         cos (x)       
4*\2 - 3*sin (x) + 3*cos (x) - 2*cos (x)*sin (x)/*cos(x)*e       *sin(x)
$$4 \left(- 2 \sin^{2}{\left(x \right)} \cos^{2}{\left(x \right)} - 3 \sin^{2}{\left(x \right)} + 3 \cos^{2}{\left(x \right)} + 2\right) e^{\cos^{2}{\left(x \right)}} \sin{\left(x \right)} \cos{\left(x \right)}$$
The graph
Derivative of y=e^(cosx^2)