Apply the quotient rule, which is:
dxdg(x)f(x)=g2(x)−f(x)dxdg(x)+g(x)dxdf(x)
f(x)=x2−6x+13 and g(x)=x−3.
To find dxdf(x):
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Differentiate x2−6x+13 term by term:
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The derivative of the constant 13 is zero.
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Apply the power rule: x2 goes to 2x
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The derivative of a constant times a function is the constant times the derivative of the function.
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Apply the power rule: x goes to 1
So, the result is: −6
The result is: 2x−6
To find dxdg(x):
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Differentiate x−3 term by term:
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The derivative of the constant −3 is zero.
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Apply the power rule: x goes to 1
The result is: 1
Now plug in to the quotient rule:
(x−3)2−x2+6x+(x−3)(2x−6)−13