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Derivative of (x^2-6x+13)/(x-3)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 2           
x  - 6*x + 13
-------------
    x - 3    
$$\frac{\left(x^{2} - 6 x\right) + 13}{x - 3}$$
(x^2 - 6*x + 13)/(x - 3)
Detail solution
  1. Apply the quotient rule, which is:

    and .

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      3. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      The result is:

    To find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      2. Apply the power rule: goes to

      The result is:

    Now plug in to the quotient rule:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
            2           
-6 + 2*x   x  - 6*x + 13
-------- - -------------
 x - 3               2  
              (x - 3)   
$$\frac{2 x - 6}{x - 3} - \frac{\left(x^{2} - 6 x\right) + 13}{\left(x - 3\right)^{2}}$$
The second derivative [src]
  /           2      \
  |     13 + x  - 6*x|
2*|-1 + -------------|
  |               2  |
  \       (-3 + x)   /
----------------------
        -3 + x        
$$\frac{2 \left(-1 + \frac{x^{2} - 6 x + 13}{\left(x - 3\right)^{2}}\right)}{x - 3}$$
The third derivative [src]
  /          2      \
  |    13 + x  - 6*x|
6*|1 - -------------|
  |              2  |
  \      (-3 + x)   /
---------------------
              2      
      (-3 + x)       
$$\frac{6 \left(1 - \frac{x^{2} - 6 x + 13}{\left(x - 3\right)^{2}}\right)}{\left(x - 3\right)^{2}}$$